Problem
$\displaystyle \int\sqrt{x}dx$
Sol$\displaystyle =\int x^{1/2}dx$
$\displaystyle =\frac23x^{\frac32}+C$
$\displaystyle =\frac23x\sqrt{x}+C$
$\displaystyle =\frac23x^{\frac32}+C$
$\displaystyle =\frac23x\sqrt{x}+C$
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