Difference between r1.4 and the current

@@ -5,7 +5,7 @@

$P(A^c)=1-P(A)$

= Proof =

$1 = P(S)$ (by axiom of probability)

$1 = P(S)$ (by axiom of probability) // [[확률공리,probability_axiom]] later

$=P(A\cup A^c)$
$=P(A)+P(A^c)$

여집합의 확률 공식 증명.

Theorem ¶

For any event $\displaystyle A$ ,

$\displaystyle P(A^c)=1-P(A)$

$\displaystyle 1 = P(S)$ (by axiom of probability) // 확률공리,probability_axiom later

$\displaystyle =P(A\cup A^c)$
$\displaystyle =P(A)+P(A^c)$